India vs Australia, 2nd ODI: Rohit Sharma beats Chris Gayle for this special record

Rohit Sharma struck a 52-ball 43 during the second ODI between India and Australia at the Adelaide Oval on Tuesday. 

His knock of 43 included two fours and two sixes and that earned him a special record across formats against an individual team. 

No player so far has hit more sixes against an opponent than Rohit across formats. He now has 89 sixes against Australia across formats, one more than Chris Gayle, who has struck 88 sixes against England.

It needed a special effort on Tuesday to dismiss Rohit and that came from Peter Handscomb. In the 16th over, bowled by Marcus Stoinis, Rohit went after a short ball but unfortunately, the centurion from the previous match mistimed the pull to be caught by Handscomb in the deep. 

Due to the excessive heat in Australia, when Handscomb ran for the catch he had a direct contact with the sun which could have resulted in Handscomb spilling it. However, the fielder made no mistake as he successfully completed the catch at the deep mid-wicket and broke into a charged up celebration. 

Earlier, Shaun Marsh smashed his seventh hundred before India pacer Bhuvneshwar Kumar produced a brilliant spell in the death overs to limit Australia to 298-9 in the second ODI. 

At the Adelaide Oval, Marsh arrived at the crease at 26-2 and scored 131 runs, including 11 fours and three sixes, and added 94 runs off 65 balls with Glenn Maxwell (48 off 37 balls).

Australia won the toss and opted to bat in searing heat. The hosts were unchanged from the previous game, while India brought in debutant Mohammed Siraj in place of Khaleel Ahmed.